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Dear CGDevToolers
is there any property in JQGrid to choose visible columns (someting like devexpress grid)

Hi fateh78,

s there any property in JQGrid to choose visible columns (someting like devexpress grid)

Yes, please check the JQGridColumnChooser.

Best Regards.

thanks Alexander

i tried to implement my own chooser by using ContextMenu with checkboxes to select visible columns as shown in attached pic.
then used the onhide event of the ContextMenu :

Code: Select all

procedure TMastersBaseForm.cmColumnChooserJQContextMenuOptionsEventsHide(Sender: TObject; AParams: TStringList);
var       i : integer;
begin
  inherited;
  for i := 0 to cmColumnChooser.JQContextMenuOptions.Items.Count-1 do begin
      grdDetailItems.JQGridColumns[i].Hidden := not cmColumnChooser.JQContextMenuOptions.Items[i].TypeCheckboxOptions.Selected;
      HeaderDataSet.Fields[i].Visible := cmColumnChooser.JQContextMenuOptions.Items[i].TypeCheckboxOptions.Selected;
  end;
  //grdDetailItems.AjaxReRender();
  grdDetailItems.JQGridOptions.RemapColumns([0,1,2,3,4,5,6,7,8,9,10], True, False);
end;


but the problem is : "cmColumnChooser.JQContextMenuOptions.Items[i].TypeCheckboxOptions.Selected" does not reflect the selected checkboxes by user.

is this a bug or i missed something ??

best regards

i missed the pic

Hi fateh78,

In this case, you need re-render the contextmenu, because this property doesn't support ajax change.

Best Regards